Impulse delivered to a sphere: Rotation motion (momentum) question

[boaty]

Homework Statement

A sphere of radius R and mass M sits on a horizontal tabletop. A horizontally directed impulse with magnitude J is delivered to a spot on the ball a vertical distance h above the tabletop.

Part 1:
Determine the angular and translational velocity of the sphere just after the impulse is delivered when...
h > R, v = ?, \omega = ?
h < R, v = ?, \omega = ?
h = R, v = ?, \omega = ?

Homework Equations

Since we're dealing with momentum, p = mv for linear momentum and L = r x p (r 'cross' p) for angular. Also, since the rotation of the sphere takes place around its axis of symmetry, L = I\omega can be used.

The Attempt at a Solution

I know when h = R, v = J/m and \omega = 0. Other than that I have no idea where to start. The help which goes with the problem said J = J_T + J_R, where the former is translational impulse, the latter, angular, but using these equations I can't get any answers (I can't even get the obvious answer I stated above).

Thanks in advance.

Edit:
I just figured out how to hack the website to give me the answer, so I don't really need help anymore. Usually the questions on the site are way more difficult than the in-class/exam questions, but if anyone still wants to post a solution, feel free. At least the question will be archived with an answer then.

 

[darkys]

Answer (for anyone who needs it):h > R, v = 0, \omega = J/Ih < R, v = J/m, \omega = 0h = R, v = J/m, \omega = 0