Impulse problem: how can these two angles be different?

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The discussion centers on the impulse experienced by a baseball after being struck by a bat, highlighting the counterintuitive nature of the impulse angle differing from the final velocity angle of the ball. The baseball, weighing 140g, initially travels at 35 m/s to the right and leaves the bat at 55 m/s to the left at a 25-degree angle. The bat imparts an impulse of 12 kg m/s to the left at an angle of 15 degrees above the horizontal. The confusion arises from the relationship between impulse and momentum, as the impulse reflects the change in momentum rather than aligning with the final velocity angle. The analysis concludes that the bat absorbs some horizontal momentum while imparting vertical momentum, resulting in differing angles for impulse and velocity.
kostoglotov
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Homework Statement



A baseball weighing 140g is traveling to the right at 35 m/s, makes contact with a baseball bat, and then leaves the bat at 55 m/s to the left at an angle 25 degrees from the horizontal.

I got the right answer, I how how the solution works mathematically.

The answer is that the bat gave the ball an impulse of 12 kg m s-1 to the left at an angle of 15 degrees above the horizontal...

This seems sooo counter-intuitive to me. How can the impulse be at a different angle from the final velocity vector that the ball got from interacting with the bat? Shouldn't they be the same angle?

Again, I know how it works mathematically, trigonometrically...I just don't get what is happening here in a physical sense.
 
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kostoglotov said:

Homework Statement



A baseball weighing 140g is traveling to the right at 35 m/s, makes contact with a baseball bat, and then leaves the bat at 55 m/s to the left at an angle 25 degrees from the horizontal.

I got the right answer, I how how the solution works mathematically.

The answer is that the bat gave the ball an impulse of 12 kg m s-1 to the left at an angle of 15 degrees above the horizontal...

This seems sooo counter-intuitive to me. How can the impulse be at a different angle from the final velocity vector that the ball got from interacting with the bat? Shouldn't they be the same angle?

Again, I know how it works mathematically, trigonometrically...I just don't get what is happening here in a physical sense.
What is the relationship between impulse and momentum ?
 
SammyS said:
How is impulse related to momentum ?

It's the change in momentum...I'm thinking now that the ball should leave at the same angle only if the ball were stationary. Given that the ball already had some horizontal momentum, the new "triangle of forces" created by the impact has a shorter horizontal component relative to it's vertical component if we were comparing it to the stationary ball case...so...the baseball bat is absorbing some of the horizontal momentum of the ball, giving some of it back, but not all of it, and also giving it some vertical momentum, and because the bat isn't returning all of the balls horizontal momentum, it can leave at a different angle to the impulse given.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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