In a typical lightning strike, 2.5 C flows from cloud to ground in 0.20 ms.

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SUMMARY

The discussion centers on calculating the current during a lightning strike, where 2.5 coulombs (C) flow from cloud to ground in 0.20 milliseconds (ms). The correct formula to use is I = Q/t, leading to a calculated current of 12500 amperes (A). However, the issue arises from the need to express the answer with the appropriate number of significant figures, as 2.5 C has only two significant digits, necessitating a final answer of 13000 A. Participants emphasize the importance of rounding and significant figures in scientific calculations.

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  • Knowledge of significant figures in scientific notation
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  • Experience with online physics homework platforms like Mastering Physics
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  • Review the concept of significant figures in calculations
  • Practice problems involving current calculations using I = Q/t
  • Explore the effects of rounding on scientific data
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csimon1
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Homework Statement



In a typical lightning strike, 2.5 c flows from cloud to ground in 0.20 ms. What is the current during the strike?

Homework Equations



I = Q/t

The Attempt at a Solution



The reason I keep getting this wrong is because it says I am rounding something off wrong. I am very confused. What I keep getting is 2.5 C/0.0002 s = 12500 A. Anyone know what I'm doing wrong?
 
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csimon1 said:

Homework Statement



In a typical lightning strike, 2.5 c flows from cloud to ground in 0.20 ms. What is the current during the strike?

Homework Equations



I = Q/t

The Attempt at a Solution



The reason I keep getting this wrong is because it says I am rounding something off wrong. I am very confused. What I keep getting is 2.5 C/0.0002 s = 12500 A. Anyone know what I'm doing wrong?

It looks correct to me; although if you are given data with accuracy of one significant figure, then you can't justify all the accuracy of your answer. Does the question want to you to give the answer with an appropriate precision?
 
It wants me to give the answer in A. This is the feedback I got:
12500 or 1.25×10e4

Not quite. Check through your calculations; you may have made a rounding error or used the wrong number of significant figures.
 
csimon1 said:
It wants me to give the answer in A. This is the feedback I got:
12500 or 1.25×10e4

Not quite. Check through your calculations; you may have made a rounding error or used the wrong number of significant figures.

Is this online?
 
yes it's using mastering physics.
 
csimon1 said:
It wants me to give the answer in A. This is the feedback I got:
12500 or 1.25×10e4

Not quite. Check through your calculations; you may have made a rounding error or used the wrong number of significant figures.

Well double check your significant figures. (i.e. 2.5 C is only 2 significant digits)
 
im sorry, i don't really understand what you mean? 2.5 C was given to me in the problem. I don't know what else to use.
 
csimon1 said:
yes it's using mastering physics.

Looks interesting. This is a product by Pearson. It is possible that there might be a glitch with the problem, but try giving the answer to a more appropriate number of figures accuracy, and see if that is accepted. You've obtained the answer 12500. But this has three figures of accuracy. What would be that value, with less precision?
 
csimon1 said:
im sorry, i don't really understand what you mean? 2.5 C was given to me in the problem. I don't know what else to use.

See: http://en.wikipedia.org/wiki/Significant_figures:
spurious digits introduced, for example, by calculations carried out to greater accuracy than that of the original data, or measurements reported to a greater precision than the equipment supports.

In this case you only have 2 relevant digits. You would have to round to 13,000 since:
leading and trailing zeros where they serve merely as placeholders to indicate the scale of the number.
 
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  • #10
ohh thank you very much i would have never gotten it otherwise!
 

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