In-frame time derivative proof

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SUMMARY

The discussion focuses on proving the in-frame time derivative D for non-inertial frames, specifically showing that D(fa) = fDa + df/dt. The scalar function f and vector a are central to this proof. The user identifies that Df = df/dt and that Da is derived from the sum of the derivatives of the components of vector a multiplied by the relevant basis vector. The proof involves recognizing that vector a is time-dependent, expressed as a · e_t, leading to the conclusion that D a = a · (d e_t/dt).

PREREQUISITES
  • Understanding of vector calculus and derivatives
  • Familiarity with non-inertial reference frames
  • Knowledge of scalar and vector functions
  • Basic principles of classical mechanics
NEXT STEPS
  • Study the properties of non-inertial frames in classical mechanics
  • Learn about the application of time derivatives in vector calculus
  • Explore the concept of basis vectors and their derivatives
  • Investigate the implications of time-dependent vectors in physics
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Students and professionals in physics, particularly those studying mechanics and vector calculus, as well as anyone interested in the mathematical foundations of non-inertial reference frames.

yakattack
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Could someone please help with this question.

For non-inertial frames show that the in-frame time derivative D obeys:
D(fa)=fDa+df/dta

Where f is a scalar function and a is a vector.

I know that Df=df/dt and that Da= the sum of the derivatives of the components of a times the relavant basis vector. But can't seem to apply this to prove the question.
 
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Well for the non inertial observer, the a vector is a time dependent function. So actually you get [tex]\vec{a} = a \cdot \vec{e_t}[/tex]. Hence the [tex]D \vec{a} = a \cdot \frac{d \vec{e_t}}{dt}[/tex].

marlon
 
Last edited:

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