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In rolling, how is Vcom related to ω?

  1. Nov 11, 2013 #1
    Everybody says that ω=v/r. But isn't that v tangent to the cirle?
  2. jcsd
  3. Nov 11, 2013 #2

    Meir Achuz

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    v is the velocity difference between the COM and the rim. The rim is at rest, so v is the velocity of the COM.
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