Inclined Plane Problem with Kinetic Friction

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The discussion centers on a problem involving kinetic friction on an inclined plane, where the user attempts to calculate the force of friction using the equation F=nukmgcos Ѳ. However, confusion arises as the scenario describes a sled being pulled over level snow, not an incline, leading to incorrect application of the physics principles. The diagram provided is also misaligned, contributing to the misunderstanding. Participants emphasize the need for clarity in both the problem title and the orientation of the diagram. Properly addressing these issues is crucial for solving the problem accurately.
physicsmaster11232
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Homework Statement
A horse pulls a 300kg sled at constant speed over level snow by a rope that is 35 degrees above the horizontal. The coefficient of friction is 0.10. Find the force the horse exerts on the rope.
Relevant Equations
F = nukFn
f=ma
mgsin Ѳ= fx
mgcos Ѳ=fy
I tried to find the force of friction using the the coefficient of kinetic friction with the equation F=nukmgcos Ѳ. Then I made the force of friction equal to the force of pull. I don't know what I'm doing wrong as I'm getting the wrong answer. I have attached a picture of my work.
 

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Your diagram is wrong. (And your title.)
physicsmaster11232 said:
over level snow by a rope that is 35 degrees above the horizontal.
What is at 35 degrees?
 
The picture of your work is not oriented properly.
 
Both the title of your question and your diagram indicate you are using the physics applicable to an inclined plane. But the question states "A horse pulls a 300kg sled at constant speed over level snow"
 
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