Inclined Plane(s) Involving Forces

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SUMMARY

The discussion focuses on solving a physics problem involving inclined planes and forces, specifically Homework #19 from a UCSD physics course. The key equation derived is mr = (ml*g*sin(60) + ml*a) / (g*sin(20) - a), where mr and ml represent the masses on the inclined planes, and g is the acceleration due to gravity. The solution process involves manipulating tension forces and applying Newton's second law (F = ma) to derive the relationship between the masses and their respective accelerations.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Basic knowledge of trigonometric functions (sine, cosine)
  • Familiarity with inclined plane mechanics
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the principles of inclined plane dynamics in physics
  • Learn how to apply trigonometric identities in force analysis
  • Explore advanced problem-solving techniques in mechanics
  • Review examples of tension forces in multi-body systems
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This discussion is beneficial for physics students, educators, and anyone interested in mastering the concepts of forces on inclined planes and applying Newtonian mechanics to solve complex problems.

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Homework Statement


Literally #19 from this link: http://physics.ucsd.edu/students/courses/summer2007/managed/physics2a/documents/chp6.pdf

The figure is not within the .pdf file, so I recreated the figure it references: http://img32.imageshack.us/img32/5701/figurephysics.png

Homework Equations


[tex]F = ma[/tex]

The Attempt at a Solution


Working the problem on my own, I only am able to get to this step, where the tension forces cancel:

[tex]m_ra + m_la = m_rg\sin(20) - m_lg\sin(60)[/tex]

... I am at a loss for the next step; particularly in the demonstrated solution, where they add and subtract the acceleration.
 
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mr*a + ml*a = mr*g*sin(20) - ml*g*sin(60)
Take all the mr terms to the left side:
mr*a - mr*g*sin(20) = -ml*g*sin(60) - ml*a
Too many minus signs so multiply everything by -1
mr*g*sin(20) - mr*a = ml*g*sin(60) + ml*a
Factor out the mr on the left side:
mr[g*sin(20) - a] = ml*g*sin(60) + ml*a
Divide both sides by the [ ] part
mr = ml*g*sin(60) + ml*a all divided by [g*sin(20) - a]
 

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