Index of refraction for converging lens

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A thin converging lens with radii of curvature R1=9cm and R2=-11cm has a focal length of 5cm. Using the Lens Maker's equation, the initial calculation for the index of refraction yielded n2=10.9, which was incorrect. The error was due to not accounting for the negative value of R2. After correcting this mistake, the accurate refractive index was determined to be 1.99. This highlights the importance of correctly applying sign conventions in optical calculations.
vetgirl1990
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Homework Statement


A thin converging lens has radii of curvature of R1=9cm and R2=-11cm. Assume its focal points F1 and F2 are 5cm from the center of the lens. Determine its index of refraction.

Homework Equations


Len's Makers equation: 1/f = (n2 - n1 / n1) (1/R1 - 1/R2)

The Attempt at a Solution


focal length f = 5cm
n1 = air = 1

Plugging in all my known values:
1/5 = (n2 - 1) (1/9 - 1/11)
n2 = 10.9

This value for refractive index doesn't make sense at all... so I'm not sure what I'm doing wrong!
 
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Did you take into account that R2 is negative?
 
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TSny said:
Did you take into account that R2 is negative?
D'oh! What a ridiculous mistake. Yes, with that taken into account the refractive index is 1.99.
 
OK, good.
 
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