Index of Refraction of Liquid: Find Value

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To find the index of refraction of a liquid with a 10 cm depth, where an object floating at the surface has its image seen 14 cm below the surface, one must consider the behavior of light as it passes through the liquid. The difference in perceived depth indicates that light bends when transitioning from air to the liquid. The image's position suggests that the index of refraction can be calculated using the formula that relates actual depth, apparent depth, and the index of refraction. Participants in the discussion emphasize the importance of posting homework questions in the designated section for better assistance. Understanding the principles of light refraction is crucial for solving this problem effectively.
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A plane mirror is placed horizoually at the bottom of a transparent liquid of 10cm depth. When one looks at the image of a small object floating at the surface of the liquid right above the object, the image is seen at 14cm below the surface of the liquid. Find the value of the index of refraction of the liquid.
 
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Please help me with some hint..
 
Try putting this in the homework section. They should be able to help you properly there!
 
Why no one help me here?
 
Voong said:
Why no one help me here?

This looks like a homework question, and per the rules of the Physics Forums all homework questions should be posted in the appropriate forum. That way the homework helpers don't have to wander around the whole forum to help you!
 
In addition, you are to show some effort yourself. What do you know about light passing through water that would help here? In particular, why would the image not be 20 cm below the surface, where it would be if there were no water?
 
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