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Index of refraction when total internal reflection ceases

  • #1
light refractions problem

I dont even know where to start with this problem. Can someone please help me out?
As shown in Figure P22.49, a light ray is incident normal to on one face of a 30°-60°-90° block of zircon(n= 1.923) that is immersed in water.


p22-49.gif

Figure P22.49
(a) Determine the exit angle 4 of the ray.
4 = wrong check mark°
(b) A substance is dissolved in the water to increase the index of refraction. At what value of n2 does total internal reflection cease at point P?
n2 =
 

Answers and Replies

  • #2
bel
155
0
For (a) : The light beam obviously entered at a normal to the shortest side of the triangular block since there wasn't any refraction, so using the fact that a triangle in a plane has a sum of internal angles of one hundred and eighty degrees, [tex]\theta_1=60^\circ [/tex]. And I suppose you know that in one single medium, for a reflection, incident angle equals reflected angle, using this, and Snell's law and the sum of internal angles for a triangle, you should be able to figure this out. Hope this helped.

For (b) : Total internal reflection occurs if critical angle is smaller than incident angle. Using Snell's law, the critical angle is the arcsine of [tex]\frac{n_2}{n_1}[/tex].
 
Last edited:
  • #3
so using the sum of internal angles it looks like theta 3 would be 30 degrees? Because if you split the reflected ray there is a 30-60-90 triangle?
 
  • #4

Homework Statement

As shown in Figure P22.49, a light ray is incident normal to on one face of a 30°-60°-90° block of zircon that is immersed in water.
p22-49.gif

(b) A substance is dissolved in the water to increase the index of refraction. At what value of n2 does total internal reflection cease at point P?


Homework Equations


theta critical= arcsin(n2/n1) and total internal reflection ceases when theta critical is less than theta incident


The Attempt at a Solution


theta 4 is 46.16. I used 59.9=arcsin(n2/1.333) and got n2=1.15 but thats not correct but i dont understand because that is when theta critical is less than theta incident. theta incident is 60
 
  • #5
andrevdh
Homework Helper
2,128
116
You need to consider total internal reflection at point P (at [tex]\theta _1[/tex]).

Also n1 is for zirconium.
 

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