1. The problem statement, all variables and given/known data a single square loop of high resistivity wire ( rho = 10^-6 ohm-meters) is placed in a constant magnetic field B of 0.3 Teslas and oriented so that the axis of rotation of the loop is perpendicular to B and in the plane of the loop. the loop rotates with an angular frequency of 300/second. a) if the square has a side length of 3 cm, what is the peak value of the voltage induced around the loop during the rotation? b) if the wire has a cross-sectional area of 10^-6 m^2, what is the value of the current induced in the loop? 2. Relevant equations angular frequency, omega = 2pi(f) where f is frequency peak voltage, V_peak(sin(omega*t)) = L(dI/dt) where t is time, dt is change in time, dI is change in current voltage V = V_peak(omega*t + phi_v) where phi_v is phase angle = 90 deg period T = 2pi(m)/qB where m is mass, q is charge, B is magnetic field current I = I_peak(sin(omega*t + phi_i) where omega is angular freq., phi_i is phase angle = 90deg voltage induced, V = (A)dB/dt where dB is change in magnetic field, dt is change in time, A is area (3*3 = 9cm^2 )= 3. The attempt at a solution i am sure i am missing equations, which equation involves magnetic field and the other givens? how does the resistivity come into play? angular freq, omega = 2pi(f) 300 = 2pi(f) frequency, f = 300/2pi = 47.74 rot/sec using "V_peak(sin(omega*t)) = L(dI/dt)" it seems i need time, if i find time, i will be able to determine V_peak for part a, as omega is given, is dI assumed constant? i am stuck on a, so haven't attempted part b, help for either part appreciated.