Induced EMF Problem: Find Emf & Current in Square Coil

[sandycow]

Homework Statement

A magnetic field is perpendicular to the plane of a single turn circular coil. The magnitude of the field is changing so that the emf of 0.80 V and a current of 3.2 A are induced in the coil. The wire is then re-formed into a single turn square coil, which is used in the same magnetic field (again perpendicular to the place of the coil and with the magnitude changing at the same rate). What emf and current are induced in the square coil?

Homework Equations

emf= ΔB/Δt*A

The Attempt at a Solution

I used the equation emf= ΔB/Δt*A. with the two areas πr^2 and 4r^2 and i thought that since they were in the same plane with the rate of change in the magnetic field the same, i could do this... 0.80V/πr^2 = emf of the square/ 4r^2 and then solve for the emf of the square since the radius cancels. my teacher gave us the answer and what i got was not correct so I am not sure which equations I am suppose to use to solve this?

 

[rl.bhat]

Hi sandycow, welcome to PF.
Your calculation of the area of the square is wrong.
What is the circumference of the given circular coil? Straighten the wire, and reform it as a square. What will be the length of each side of the square? What is the area of the square?

 

[sandycow]

ohhhhh. i get it haha thanks that was such an oversight.