Induction Motors: Power Consumed vs Power Delivered

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The discussion centers on the power consumption and delivery of three-phase induction motors. The power consumption is calculated using the formula P = sqrt(3)*V*I*(PF), which yields a value of 19.6 kW for a motor operating at 460 volts and 30 amps with a power factor of 0.82. Participants clarify that the power delivered to the motor is essentially the same as the power consumed, but losses such as iron, copper, and mechanical friction prevent the output mechanical power from matching these values. The key distinction lies in the difference between electrical input power and mechanical output power, emphasizing motor efficiency. Understanding these concepts is crucial for evaluating motor performance and efficiency.
Bergenheimer
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Hello

The equation for power consumption of a three phase induction motor is given by the equation:

P = sqrt(3)*V*I*(PF)

Does this differ from the power that is delivered to the motor. For example, if a motor is running at 460 volts, 30 amps with a PF of 0.82, then the power consumption is

P = sqrt(3)*460*30*.82 = 19.6 kW

What is the corresponding power being delivered to the motor? is it the same value? Just want to know if the power being delivered to the motor is different than the power the motor actually consumes.



Bergenheimer
 
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Hi
One basic question, how it would be possible, that power delivered wouldn't be consumed ?

Equations you are writing here are describing power delivered = consumed (consumed in many ways - iron losses, copper losses, friction, ventilation, mechanical power output).

There is one more thing: difference between power output (mechanical power on shaft) and power input (your equations). Maybe you are referring to this ?
 
Hello Berg:

Your OP - refers to "power consumed" and "Delivered to", these are the same thing and referring to the electrical circuit - a matter of perspective, from the sources perspective or from the motors perspective. It is the Mechanical Power (shaft) output of the motor that will not equal these values due to losses in the motor - both electrically and mechanically. The better the motor - the better the efficiency etc.
 
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