Induction stovetop design: am I using these equations correctly?

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An effective induction stovetop requires around 1000W of power, and the user is working with magnet wire that can handle a maximum of 0.2A. They calculated the energy stored in an inductor using the formula E = 0.5*I^2*L, leading to a derived inductance (L) of 1.2mH for the desired power output. The user also determined that to achieve this inductance with a coil of 10 turns, the area must be approximately 10 times the length. However, they realized that achieving the necessary voltage of 5000V from standard wall outlets is impractical, raising concerns about their calculations and feasibility.
nagyn
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I am trying to make an induction stovetop using some magnet wire. I understand how induction stovetops work but am less confident on the math I've done to design one. Can you double-check that I'm approaching this correctly?
I've been told an effective induction stovetop needs to deliver about 1000W of power. I have magnet wire that can tolerate at most about 0.2A of current, and was planning on using a 60Hz wall outlet as my source (obviously I'll need to bring down the outlet current quite a bit).

So the energy stored in an inductor is given by:

E = 0.5*I2*L

Which I assume would be roughly the same energy transferred to the pot when on the stove. So the power delivered would be

P = E / t = E*(60 Hz)

Then substituting P = 1000W and I = 0.2A I get that L = 1.2mH.

Then given that L = μ0*N2*A / ι , I find that I need a ratio close to

N2*A / ι = 952

So if I had a coil with 10 turns, the area would need to be about 10 times the length to deliver the power I need.

Am I doing this right? Did I mess up anywhere in my understanding?
 
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Power in Watts = Volts * Amps
Watts / Amps = Volts
1000 / 0.2 = 5000V.

:cry: Sorry, I don't know of anyplace that has 5000 Volts at their wall outlets.
 
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