Inductor Circuit Simulation: Understanding Current Rise and Voltage Output

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SUMMARY

The discussion focuses on simulating an inductor circuit where the inductor current reaches 500mA and the output voltage (Vout) is 5V. The time constant for the circuit is calculated as L1/R1 = 10µs, and the equation governing the current behavior is i(t) = V/R (1 - e^(-Rt/L)). The simulation parameters include using a V1 pulse with initial voltage 0V, Von 5V, Tdelay 5µs, and a .TRAN stop time of 100µs. Observing the transient waveform reveals the current rise over approximately 50µs, confirming the expected behavior.

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  • Understanding of inductor circuit behavior
  • Familiarity with time constant calculations
  • Knowledge of transient analysis in circuit simulation
  • Proficiency in using simulation tools like SPICE
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Electrical engineers, circuit designers, students studying electromagnetism, and anyone involved in simulating inductor circuits will benefit from this discussion.

PhysicsTest
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TL;DR
To understand the inductor circuit.
I am trying to understanding the inductor circuit. I have drawn the below circuit and try to simulate
1635602554158.png

The Inductor current comes to 500mA and Vout is 5V as per simulation. The current in inductor should slowly increase from 0A to 500mA but i cannot see that in the waveform. Is my understanding correct?
 
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PhysicsTest said:
but i cannot see that in the waveform
Neither can we. What waveform ?
Do you have some equations to describe the behaviour of your circuit ?

##\ ##
 
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I'm not sure about "slowly".
The time constant for this circuit is L1/R1 = 10uSec.
 
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1635604571909.png

This is the output waveform i can get. Ok now i started writing the equation for the circuit.
##i(t) = \frac{V} {R} (1 - e^{\frac{-Rt} L})##
Substituting the values
##i(1) = 5/10*(1 - e^{-10^5}) ##
##i = 0.5A##. The answer is matching.
 
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So zoom into the first few us of the transient waveform to see the LR time constant...
 
The DC analysis sets up 500 mA before the run.
You must use; V1 pulse; initial=0V; Von=5V; Tdelay=5usec;
and .TRAN stop time = 100 usec.
Then see the current rise over about 50 usec.
Inductor.png
 
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