Inelastic collision and angular velocity

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The discussion revolves around a perfectly inelastic collision between two identical particles, where one is initially at rest and the other moves with velocity v0. The user attempts to calculate the post-collision velocity (v1) and angular velocity (omega1) using conservation laws, but encounters discrepancies in kinetic energy calculations, suggesting potential errors in their approach. They consider modeling the second particle as a point mass to determine angular momentum but question whether to use the point of contact or the center of the second particle for calculations. The user is seeking confirmation on their methodology and whether their assumptions about angular momentum and energy conservation are correct.
Lord Crc
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Homework Statement


Hi, I would just like to know if I'm on the right track with this one.

I have two identical particles with a radius R and mass M. One is at rest and the other moves directly down with a velocity v0. The second particle hits the first particle slightly offset, so that the angle between the horizontal and the line connecting the centers of mass is theta. The collision is perfectly inelastic. The moment of inertia around the center of mass for one particle is Ic, and around the center of mass of the combined particles I.

a) what is the velocity v1 after the collision?
b) what is the angular velocity omega1 after the collision?

Homework Equations



Inelastic collision: m_a\vec{v}_{a0} + m_b\vec{v}_{b0} = (m_a + m_b)\vec{v}_1

Angular momentum: L = I\omega

Angular momentum of a particle: L = mvr\sin\phi

Conservation of angular momentum: L_0 = L_1 or I_0\omega_0 = I_1\omega_1

The Attempt at a Solution



a) I just use the equation for inelastic collision and get \vec{v}_1 = \frac{1}{2}\vec{v}_0, or?

b) Since the first particle is said to be at rest, and the assignment doesn't mention what the angular velocity of each particle is before the collision, I'll assume that neither is rotating before the collision. So, I'm thinking I can find the angular momentum pre-collision by modeling the second particle as a point mass 2R away from the center of the first, and this would be L0, so that L_0 = mvr sin\phi = 2mv_0R sin\phi. Using some trigonometric argument I'll find an expression for phi based on theta (I don't expect to have a problem with this). I then use conservation of angular momentum and solve for omega1. Does this sound right?
 
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I've now tried this approach, and it seems not to work out quite right. That is, I have to find the kinetic energy before and after the collision, and using the angular velocity I got from the above approach I get a larger kinetic energy after the collision than before. I can't find any fault in my equations when finding the kinetic energy, so I'm inclined to think the above approach is wrong.

For instance should I use the point of contact or the center of the second particle when finding the angular momentum L0?
 
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