Inelastic collision between two footballs players on ice

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Homework Help Overview

The problem involves an inelastic collision between two football players sliding on a frictionless ice surface. The players have different masses and velocities, and the discussion centers around calculating their combined velocity after the collision and the fraction of kinetic energy retained post-collision.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the calculation of initial and final kinetic energy, with one participant attempting to derive a constant related to energy conservation. Questions arise regarding the correctness of the approach and the calculations involved.

Discussion Status

Some participants are exploring the calculations for kinetic energy and questioning the methods used. One participant claims to have arrived at the correct answer, while another offers a welcome and encouragement, indicating a supportive environment.

Contextual Notes

There is mention of confusion regarding the calculations and the approach to finding the fraction of kinetic energy retained, suggesting that assumptions or methods may need clarification.

irishbob
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Homework Statement


An American football game has been canceled because of bad weather in Cleveland, and two retired players are sliding like children on a frictionless ice-covered parking lot. William 'Refrigerator' Perry, mass 162 kg, is gliding to the right at 7.41 m/s, and Doug Flutie, mass 81.0 kg, is gliding to the left at 11.0 m/s along the same line. When they meet, they grab each other and hang on.
(a) What is their velocity immediately thereafter?
1.273 m/s

(b) What fraction of their original kinetic energy is still mechanical energy after their collision?



Homework Equations


KE_i=KE_f*c? This is kind of my issue.
KE_i is initial kinetic energy, KE_f is final kinetic energy, and c is a constant.


The Attempt at a Solution


Well I'm trying for the fraction of the energy:
Sum(KE_i)=0.5*162kg(7.41m/s)^2 + 0.5(81kg)(-11m/s)^2
=9348.0561=.5(162+81)kg(1.273m/s)^2c=KE_f*c
So I solved for c and got 6.890. Problem is, I have no idea what to do with it. Am I approaching this the right way?
 
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You are getting the wrong answer due to your math and partly due to your approach. How did you get c=6.89? Anyway, what is the final mechanical energy (without any constant)? What is the initial kinetic energy? The final mechanical energy is a small percentage of the initial kinetic energy.
 
Got the correct answer. Thanks! I don't know why I was doing it that way.
 
OK, and welcome to Physics Forums!:cool:
 
Thanks! :smile:
I'm a long time lurker, first time poster.
 

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