Inelastic Collision Using Distance to Figure Velocity

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SUMMARY

The discussion focuses on calculating the velocity of a knife thrown in a perfectly inelastic collision scenario from the movie "V for Vendetta." The knife weighs 0.567 kg, and it knocks a bodyguard weighing 104.8 kg back 1.52 meters. The initial velocity of the bodyguard is 0 m/s. The user determined the bodyguard's final velocity by accounting for the film's speed reduction of 1/4 and measuring the time taken to travel the distance. This method, while effective, raises concerns about the accuracy due to the number of variables involved.

PREREQUISITES
  • Understanding of inelastic collisions in physics
  • Knowledge of basic kinematics and velocity calculations
  • Familiarity with the concept of momentum conservation
  • Ability to analyze motion using distance and time measurements
NEXT STEPS
  • Study the principles of momentum conservation in inelastic collisions
  • Learn how to calculate velocity using kinematic equations
  • Explore the effects of external factors on projectile motion
  • Investigate the impact of video frame rate on motion analysis
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in applying physics concepts to real-world scenarios, particularly in analyzing motion and collisions in film and media.

Luudy
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For my intro to physics class, we have to do a project known as Phylm, in which we analyze a scene from a movie that utilizes physics in some way and then determine, based on our findings, whether the situation is viable or not. I'm using the scene from V for Vendetta in which V throws a pair of knives and knocks two bodyguards back approximately 1.52 Meters. My question is, using the data below, how do I figure out the velocity of the knife, and then how much force it would take a man to throw the knife at that velocity? The collision is perfectly inelastic.

Weight of knife (a): .567 Kg
Weight of bodyguard: 104.8 Kg
Distance bodyguard travels after being hit: 1.52 m
Initial velocity of bodyguard: 0 m/s2
 
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I'm afraid you're going to have to give it a bit of a go yourself before anyone leaps to your assistance. (It might also be a good idea to use the forum's homework template.)
 
I've actually got it now, chief. I just figured out how much the film had been slowed down from normal, which was down by 1/4, and then figured out the bodyguard's final velocity based on how long it took him to fall backwards the 1.52 meters. If there's a better way to do it, though, it would be much appreciated. I feel like I had to guess about too many variables this way.
 

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