1. The problem statement, all variables and given/known data In the figure provided, two suitcases are on a 6.36 m high ramp to passengers waiting in a baggage terminal. The top suitcase is released from rest, and it slides down the ramp and hits the second suitcase. If the suitcase at the top has a mass of 11.8 kg and the other suitcase has a mass of 23.6 kg, what is their combined speed if an inelastic collision is achieved? Assume the ramp to be frictionless. 2. Relevant equations KE = (1/2)*mv2 PE = mgh m1v1+m2v2 = (m1+m2)v 3. The attempt at a solution I just had a question about whether this is the approach to solve this question or not. So since the ramp is frictionless, total mechanical energy is conserved. You use mgh = (1/2)*mv2 , isolate v and solve for v for the first suitcase. Then with the v you plug it into the inelastic collision formula to solve for the new combined velocity of the two suitcases. m1v1+m2v2= (m1+m2)v Isolate for v and v2 is 0?