- #1

- 99

- 2

## Homework Statement

(x-2)/(x+3) less than (x+1)/(x)

## The Attempt at a Solution

I broke it up into cases.

When x+3 less than 0 and x less than 0

and then when both are positive, when one is positive and the other is negative and then the other way around.

I'm not sure if that's the right way though. I was thinking that maybe you can say:

(x+3)(x) less than 0

and a second case

(x+3)(x) greater than 0