Inferring A General Term From A Sequence

  • Thread starter Bashyboy
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  • #1
Bashyboy
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Homework Statement


3, -3/2, 3/4, -3/8,...


Homework Equations





The Attempt at a Solution


I began to write, [itex](-1)^{n+1} \frac{3}{...}[/itex], but I began to despair once I came upon the denominator. I know that every term's, except 3, denominator can be written as a power of two, but I wasn't sure on how to account for the 3.
 

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  • #2
LCKurtz
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Homework Statement


3, -3/2, 3/4, -3/8,...


Homework Equations





The Attempt at a Solution


I began to write, [itex](-1)^{n+1} \frac{3}{...}[/itex], but I began to despair once I came upon the denominator. I know that every term's, except 3, denominator can be written as a power of two, but I wasn't sure on how to account for the 3.

I don't see your problem. You have the alternating sign, the 3, and powers of two. Put them all in your answer.
 
  • #3
Bashyboy
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So, would it be [itex](-1)^{n+1} \frac{3}{2^{n-1}}[/itex]
 
  • #4
LCKurtz
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So, would it be [itex](-1)^{n+1} \frac{3}{2^{n-1}}[/itex]

All you have to do is see if it gives your answers for n = 1,2,3,4.
 

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