# Inferring A General Term From A Sequence

## Homework Statement

3, -3/2, 3/4, -3/8,...

## The Attempt at a Solution

I began to write, $(-1)^{n+1} \frac{3}{...}$, but I began to despair once I came upon the denominator. I know that every term's, except 3, denominator can be written as a power of two, but I wasn't sure on how to account for the 3.

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LCKurtz
Homework Helper
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## Homework Statement

3, -3/2, 3/4, -3/8,...

## The Attempt at a Solution

I began to write, $(-1)^{n+1} \frac{3}{...}$, but I began to despair once I came upon the denominator. I know that every term's, except 3, denominator can be written as a power of two, but I wasn't sure on how to account for the 3.
I don't see your problem. You have the alternating sign, the 3, and powers of two. Put them all in your answer.

So, would it be $(-1)^{n+1} \frac{3}{2^{n-1}}$

LCKurtz
So, would it be $(-1)^{n+1} \frac{3}{2^{n-1}}$