Infinite Series Convergence using Comparison Test

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The series ∑ (1 / (3n + cos²(n))) is analyzed for convergence using the Comparison Test. The dominant term in the denominator is 3n, while cos²(n) oscillates between 0 and 1. It is established that 1 / (3n + cos²(n)) is less than or equal to 1 / 3n, which is a convergent geometric series. Therefore, the series converges by the Comparison Test. The discussion highlights the importance of correctly accounting for the behavior of cos²(n) in the analysis.
titasB
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Homework Statement



Determine whether the series is converging or diverging

Homework Equations




∑ 1 / (3n +cos2(n))
n=1

The Attempt at a Solution



I used The Comparison Test, I'm just not sure I'm right. Here's what I've got:

The dominant term in the denominator is is 3n and
cos2(n) alternates between 0 and 1

so,

1 / (3n +cos2(n)) < 1 / 3n

which is convergent geometric series, since | r | = 1/3 < 1

And so, 1 / (3n +cos2(n)) is convergent according to the Comparison Test
 
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looks ok to me. actually maybe you should change < to ≤ for when cos2 is zero
 
Last edited:
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Likes titasB
Thanks. Wasn't sure about the cos2(n) part
 

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