Infinite Series Convergence using Comparison Test

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SUMMARY

The series ∑ (1 / (3n + cos²(n))) from n=1 to ∞ converges based on the Comparison Test. The dominant term in the denominator is 3n, while cos²(n) oscillates between 0 and 1. By comparing the series to the convergent geometric series ∑ (1 / 3n), it is established that since |r| = 1/3 < 1, the original series converges. It is recommended to use ≤ instead of < when cos²(n) equals zero for accuracy.

PREREQUISITES
  • Understanding of the Comparison Test in series convergence
  • Familiarity with geometric series and their convergence criteria
  • Knowledge of trigonometric functions, specifically cos²(n)
  • Basic calculus concepts related to infinite series
NEXT STEPS
  • Study the Comparison Test in more detail, focusing on its applications in series convergence
  • Learn about geometric series and their convergence properties
  • Explore the behavior of trigonometric functions in series
  • Investigate other convergence tests such as the Ratio Test and Root Test
USEFUL FOR

Students studying calculus, particularly those focusing on series convergence, as well as educators teaching series and convergence tests.

titasB
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Homework Statement



Determine whether the series is converging or diverging

Homework Equations




∑ 1 / (3n +cos2(n))
n=1

The Attempt at a Solution



I used The Comparison Test, I'm just not sure I'm right. Here's what I've got:

The dominant term in the denominator is is 3n and
cos2(n) alternates between 0 and 1

so,

1 / (3n +cos2(n)) < 1 / 3n

which is convergent geometric series, since | r | = 1/3 < 1

And so, 1 / (3n +cos2(n)) is convergent according to the Comparison Test
 
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looks ok to me. actually maybe you should change < to ≤ for when cos2 is zero
 
Last edited:
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Likes   Reactions: titasB
Thanks. Wasn't sure about the cos2(n) part
 

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