Infinite Square Well with Multiple Particles

[sarahjohn]

Homework Statement

An infinitely deep square well has width L = 2.5 nm. The potential energy is V = 0 eV inside the well (i.e., for 0 ≤ x ≤ L). Seven electrons are trapped in the well.

1)What is the ground state (lowest) energy of this seven electron system?
2)What is the energy of the first excited state of the system?
NOTE: The first excited state is the one that has the lowest energy that is larger than the ground state energy.
3)What is the energy of the second excited state of the system?

Relevant Equations

En = (h^2 * n^2) / (8 * m * L^2)

Using the equation En = (h²*n² ) / (8*m*L²), I got that E1 = 0.06017eV but the answer is not correct.

 

[TSny]

Have you taken into account that you have seven electrons?

 

[sarahjohn]

Have you taken into account that you have seven electrons?

I realized that was my mistake and figured it out. Thank you!