Infinite Square Well with Multiple Particles

AI Thread Summary
The discussion revolves around calculating energy levels in an infinite square well for a system with multiple particles, specifically seven electrons. The initial calculation using the formula En = (h2*n2) / (8*m*L2) yielded an incorrect energy value of E1 = 0.06017 eV. The error was identified as failing to account for the presence of seven electrons in the system. After acknowledging the mistake, the user successfully resolved the issue. This highlights the importance of considering particle interactions in quantum mechanics calculations.
sarahjohn
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Homework Statement
An infinitely deep square well has width L = 2.5 nm. The potential energy is V = 0 eV inside the well (i.e., for 0 ≤ x ≤ L). Seven electrons are trapped in the well.

1)What is the ground state (lowest) energy of this seven electron system?
2)What is the energy of the first excited state of the system?
NOTE: The first excited state is the one that has the lowest energy that is larger than the ground state energy.
3)What is the energy of the second excited state of the system?
Relevant Equations
En = (h^2 * n^2) / (8 * m * L^2)
Using the equation En = (h2*n2 ) / (8*m*L2), I got that E1 = 0.06017eV but the answer is not correct.
 
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Have you taken into account that you have seven electrons?
 
TSny said:
Have you taken into account that you have seven electrons?
I realized that was my mistake and figured it out. Thank you!
 
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