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Infinite Well with Schrodinger equation

  1. Jul 2, 2013 #1
    1. The problem statement, all variables and given/known data
    I'm having a bit of trouble following my textbook, I was under the impression ψ(x) = e^i(kx) = Cos(kx) + iSin(kx) but in my textbook they write the general solution to this equation as ψ(x) = ASin(kx) + BCos(kx). How come they wrote the sin part as not imaginary? isn't this suppose to be a complex number? I know this example is like the most common example for introduction to quantum physics classes so I'm hoping somebody can give me some insight here
     
  2. jcsd
  3. Jul 2, 2013 #2

    mfb

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    Staff: Mentor

    A and B are complex numbers.
    A=i and B=1 is a special case of the more general solution.
     
  4. Jul 2, 2013 #3
    A and B are BOTH complex numbers??? oh geeez this stuff is more confusing than i thought!
     
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