QM solutions to the Schrodinger Equation

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SUMMARY

The discussion centers on solving the time-independent Schrödinger Equation for a piecewise potential defined as V(x) = Vo for x < 0 and x > a, and V(x) = 0 for 0 < x < a. In the region where V(x) = 0, the wave function solutions are expressed as ψ = Asin(kx) + Bcos(kx), where k² = -2mE/ħ². Conversely, in the regions where V(x) = Vo, the solutions take the form of complex exponentials due to the equation ψ'' + f²ψ = 0, with f² = -2m(E - V0)/ħ². The equivalence of these solutions is established through the identities involving complex exponentials, highlighting the practicality of the exponential form for manipulation.

PREREQUISITES
  • Understanding of the time-independent Schrödinger Equation
  • Familiarity with piecewise potential functions
  • Knowledge of wave function solutions in quantum mechanics
  • Proficiency in complex numbers and their identities
NEXT STEPS
  • Study the derivation of the time-independent Schrödinger Equation
  • Explore the implications of boundary conditions on wave functions
  • Learn about the significance of complex exponentials in quantum mechanics
  • Investigate the physical interpretation of wave functions in quantum systems
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Students of quantum mechanics, physicists working with wave functions, and anyone interested in the mathematical foundations of quantum theory.

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Homework Statement



Here's something that's confusing me. Say we have a potential

V(x) = Vo if x < 0, x > a
and
V(x) = 0 if 0 < x < a

(yes I know the notation with greater than/equals etc isn't totally correct, but you know what I'm talking about.)

In the middle section, ψ'' + k2ψ = 0

Whenever I see the solutions it's always ψ = Asin(kx) + Bcos(kx) in the middle section where k2 = -2mE/h2

In the right/left sections, ψ'' + f2ψ = 0, with f2 = -2m(E - V0)/h2

The solutions here always seem to be complex exponentials.

Can someone please explain the difference to me in the solutions?
 
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You must know the identities:
exp(±iø) = cosø ± i*sinø
So the two sets of solutions you're referring to are basically equivalent once you take the real part, only the exponential form turns out to be more practical in most cases because easier to manipulate.
 

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