stglyde said:
How come a "positive-energy false vacuum would, according to general relativity, generate an exponential expansion of space"?
If we have a smoothly-distributed energy density, then the expansion of space (neglecting spatial curvature) can be written as:
[tex]H(t)^2 = \rho(t)[/tex]
(neglecting constants for clarity)
This can be derived directly from the Einstein field equations in General Relativity. Here [itex]H(t)[/itex] is the expansion rate, defined as:
[tex]H(t) = {1 \over a(t)}{d \over dt}a(t)[/tex]
...and [itex]\rho(t)[/itex] is the energy density of the universe. Now, if the energy comes just from a false vacuum, then that energy is a constant. So if we define [itex]H_0 = H(t=0)[/itex], then we can simply write:
[tex]{1 \over a}{da \over dt} = H_0[/tex]
So now we have a simple differential equation. I can then multiply both sides by the scale factor [itex]a[/itex] to put the differential equation in a more familiar form:
[tex]{da \over dt} = H_0 a[/tex]
If you know your most basic differential equations, this should look very familiar to you: the rate of change in the scale factor is proportional to the scale factor. This is the equation for exponential growth!
[tex]a(t) = a(t=0) e^{H_0 t}[/tex]
(If you're having difficulty, think compound interest: the amount added to your bank account each month is proportional to your balance, which means that your bank account balance grows exponentially).