Initial condition of Wave functions with Yukawa Potential

Click For Summary
The discussion centers on solving the eigenvalue problem of the Schrödinger equation with Yukawa potential, specifically regarding the boundary conditions for eigenfunctions. It is suggested that the boundary conditions may be similar to those of the Coulomb potential, particularly as the exponential term approaches 1 when r approaches 0. However, it is emphasized that the wavefunction must tend to zero as r approaches infinity to find the eigenvalue correctly. Participants also request references for further reading on these boundary conditions and proper LaTeX formatting. The conversation highlights the importance of careful consideration of boundary conditions in quantum mechanics.
Riccardo Marinelli
Messages
5
Reaction score
1
Homework Statement
Find eigenfunctions of Schrödinger equation with Yukawa potential
Relevant Equations
$$V(r)=-\frac{1}{r}\exp{-\frac{r}{r_0}}$$
Hello, I was going to solve with a calculator the eigenvalues problem of the Schrödinger equation with Yukawa potential and I was thinking that the boundary conditions on the eigenfunctions could be the same as in the case of Coulomb potential because for r -> 0 the exponential term goes to 1, am I right or have I to be more careful?
In the case I'm wrong do you know some articles or books where I can find some information about these conditions?
 
Last edited:
Physics news on Phys.org
correct and the wave function needs to go to 0 as r \rightarrow \infty
 
Yes, in order to find the eigenvalue I impose that the wavefunction goes to zero, thank you
 
Riccardo Marinelli said:
Homework Statement:: Find eigenfunctions of Schrödinger equation with Yukawa potential
Relevant Equations:: $V(r)=-\frac{1}{r}\exp{-\frac{r}{r_0}}$

Hello, I was going to solve with a calculator the eigenvalues problem of the Schrödinger equation with Yukawa potential and I was thinking that the boundary conditions on the eigenfunctions could be the same as in the case of Coulomb potential because for r -> 0 the exponential term goes to 1, am I right or have I to be more careful?
In the case I'm wrong do you know some articles or books where I can find some information about these conditions?

You're a couple of dollars short there:
$$V(r)=-\frac{1}{r}\exp{-\frac{r}{r_0}}$$
 
  • Like
Likes TSny and Riccardo Marinelli
Thank You ! I was wondering how to insert Latex properly!
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 19 ·
Replies
19
Views
2K
Replies
7
Views
2K
  • · Replies 19 ·
Replies
19
Views
3K
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K