Initial-Value Problem: Rewriting Equation for Easier Derivative Calculation

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SUMMARY

The discussion centers on rewriting the equation \(((e^t)^2)(dy/dt) + (e^t)^2 (t)(y) = t^3((e^t)^2)\) to facilitate easier derivative calculations for initial value problems. The participant expresses frustration with the integrating factor method and seeks clarification on the application of the product rule and the common factor \(e^{2t}\). The key takeaway is the importance of recognizing common factors and applying the product rule correctly to simplify the equation for derivative evaluation.

PREREQUISITES
  • Understanding of differential equations and initial value problems
  • Familiarity with the product rule in calculus
  • Knowledge of integrating factors in solving differential equations
  • Basic proficiency in exponential functions and their derivatives
NEXT STEPS
  • Review the product rule in calculus for derivative calculations
  • Study the method of integrating factors for first-order linear differential equations
  • Practice rewriting differential equations to identify common factors
  • Explore examples of initial value problems and their solutions
USEFUL FOR

This discussion is beneficial for students studying differential equations, particularly those struggling with initial value problems and the application of calculus rules such as the product rule and integrating factors.

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Homework Statement



((e^t)^2)(dy/dt) + (e^t)^2 (t)(y) = t^3((e^t)^2)

The Attempt at a Solution



Im suppost to figure out how to rewrite the left side of this equation so when you take the derivative of it, it becomes the current left side of the equation as you see it now. we are doing this so we can solve initial value problems however i am stuck. I know the product rule is involved but it was so long ago that i don't remember it.
 
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Is this right? e^(2t) seems to be common.
 
shramana said:
Is this right? e^(2t) seems to be common.

Its these stupid integrating factor method. i swear to god I am doing it right and I am so mad. I am convinced webworks is not working for me. Thankyou for your help
 

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