Initial Velocity of a dropped object problem

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The discussion clarifies the concept of initial velocity for objects in motion. When an object is dropped, its initial velocity is considered 0 m/s at the moment it leaves the hand, as it has not yet begun to move downwards. Conversely, when an object is thrown upwards at 25 m/s, that speed is its initial velocity immediately after leaving the hand. The confusion arises from measuring velocity while the object is still in hand versus after it begins motion. Understanding these distinctions is crucial for correctly applying the concept of initial velocity in physics problems.
sinchan
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Why we take initial velocity of dropped object downwards as 0 and 25m/s when the object is thrown 25m/s upwards ?

What is then initial velocity cause when t=0 both object dropping and moving upwards had 0 velocity - in other words when object came to motion at both places it had some velocity?
 
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sinchan said:
Why we take initial velocity of dropped object downwards as 0 and 25m/s when the object is thrown 25m/s upwards ?

What is then initial velocity cause when t=0 both object dropping and moving upwards had 0 velocity - in other words when object came to motion at both places it had some velocity?
Are you saying that, when you throw a ball, its velocity is zero when it leaves your hand? And, when you drop a ball, its velocity isn't zero when it leaves your hand?
 
Chestermiller said:
Are you saying that, when you throw a ball, its velocity is zero when it leaves your hand? And, when you drop a ball, its velocity isn't zero when it leaves your hand?

I can state better when I understand initial velocity - for me when object is dropped from height or thrown with a velocity upwards both of them has velocity zero when it is in hand but both of them have a velocity when it leaves the hand - but then I am not sure when do we measure initial velocity - when it is in hand or when it just started its moion - so when it is in hand for both case initial velocity is 0 and when it started its motion both of them have a velocity - so why we say that initial velocity of object dropped is 0 while 25 m/s when object is thrown upwards as in my example
 
sinchan said:
I can state better when I understand initial velocity - for me when object is dropped from height or thrown with a velocity upwards both of them has velocity zero when it is in hand but both of them have a velocity when it leaves the hand - but then I am not sure when do we measure initial velocity - when it is in hand or when it just started its moion - so when it is in hand for both case initial velocity is 0 and when it started its motion both of them have a velocity
This is not correct. When you throw something, the velocity of the object just before it leaves your hand is the same as its velocity just after it leaves your hand (>0). And when you drop something, its velocity just before it leaves your hand is the same as its velocity just after it leaves your hand (=0).
 
i understand your confusion...When you drop a ball, its velocity increases by every second.It becomes 9.8 m/s 1 second after leaving your hand.However, when you throw a ball, the only reason the ball goes out from your hand is because your provided it with acceleration, which caused it to have a velocity, which started its motion, hence its "initial" velocity. When you dropped the ball, the velocity at which the "downwards" motion of ball started is 0 m/s...
Hope this helps
 
For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

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