Initially charged capacitor disharged through a resistor

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
4 replies · 7K views
Mike88
Messages
6
Reaction score
0

Homework Statement


A capacitor with initial charge q0 is discharged through a resistor.
(a) In terms of the time constant τ, how long is required for the capacitor to lose the first one-third of its charge? answer x tau
(b) How long is required for the capacitor to lose the first two-thirds of its charge?
answer x tau



Homework Equations


i = -(q0/RC)e(-t/RC)


The Attempt at a Solution


I tried solving for time t and got -RC*ln(q/q0)= t
I'm lost i don't know what to do
 
Physics news on Phys.org
Mike88 said:
I tried solving for time t and got -RC*ln(q/q0)= t
Looks good to me (except for the minus sign). So what's the time when q = q0/3?
 
Doc Al said:
Looks good to me (except for the minus sign). So what's the time when q = q0/3?

i then get t = RC*ln(1/3) where RC = tau

is this correct?
 
Last edited:
Mike88 said:
i then get t = RC*ln(1/3) where RC = tau

is this correct?
Yes. But put that minus sign back in. (I didn't see that you had q0 on top! :wink:)
 
Doc Al said:
Yes. But put that minus sign back in. (I didn't see that you had q0 on top! :wink:)

thanks for the help i figured out everything.