1. The problem statement, all variables and given/known data Two identical capacitors Ca and Cb each of capacitance 6.60 http://lon-capa.mines.edu/adm/jsMath/fonts/cmmi10/alpha/100/char16.png F are connected in parallel across a CONSTANT total electric potential difference of 480 V. A dielectric slab of dielectric constant 4.65 can fill Ca and is slowly inserted into that capacitor. What is the change in charge, [PLAIN]http://lon-capa.mines.edu/adm/jsMath/fonts/cmr10/alpha/100/char01.pngQa, [Broken] on Ca when the dielectric is added to Ca? 2. Relevant equations C=Q/V 3. The attempt at a solution Ca+Cb= Qtotal/480 Qtotal/2=Qa initial because they have the same capacitance Ca=kQa final/480 Qa final- Qa initial = Change in Qa Any help would be greatly appreciated.