Two identical capacitors Ca and Cb each of capacitance 6.60 http://lon-capa.mines.edu/adm/jsMath/fonts/cmmi10/alpha/100/char16.png F are connected in parallel across a CONSTANT total electric potential difference of 480 V. A dielectric slab of dielectric constant 4.65 can fill Ca and is slowly inserted into that capacitor.
What is the change in charge, [PLAIN]http://lon-capa.mines.edu/adm/jsMath/fonts/cmr10/alpha/100/char01.pngQa, [Broken] on Ca when the dielectric is added to Ca?
The Attempt at a Solution
because they have the same capacitance
Qa final- Qa initial = Change in Qa
Any help would be greatly appreciated.
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