Instantaneous Particle Velocity from Wave

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The discussion revolves around calculating the instantaneous velocity of a particle using the displacement equation D(x,t) = Asin(kx-ωt+ϕ). The derivative of displacement, D'(x,t) = -ωAcos(kx-ωt+ϕ), is derived to find the velocity. The user is unsure how to obtain a numerical answer due to the lack of specific values for time or distance. A suggestion is made to use the position at point 1, where it is zero, to determine the phase and subsequently calculate the velocity. This approach provides a method to solve for instantaneous velocity despite the initial uncertainty.
rocapp
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Homework Statement


See the attached picture.



Homework Equations


D(x,t) = Asin(kx-ωt+ϕ)


The Attempt at a Solution


The instantaneous velocity of a particle would be the derivative of displacement:
D'(x,t) = -ωAcos(kx-tω+ϕ)

Then plug in the known values:
= -18.84cos((π/15)x-3πt)

The above should be the answer, but since I do not have a specified value for time or distance, I am not sure how to come to a numerical answer. Thanks in advance!
 

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rocapp said:
since I do not have a specified value for time or distance
You have an indirect one: At point 1, the position is 0. This allows to determine a value for the phase (kx-ωt+ϕ), which you can use in the equation for the velocity.
 
Thanks!
 
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