Instantaneous Particle Velocity from Wave

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rocapp
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Homework Statement


See the attached picture.



Homework Equations


D(x,t) = Asin(kx-ωt+ϕ)


The Attempt at a Solution


The instantaneous velocity of a particle would be the derivative of displacement:
D'(x,t) = -ωAcos(kx-tω+ϕ)

Then plug in the known values:
= -18.84cos((π/15)x-3πt)

The above should be the answer, but since I do not have a specified value for time or distance, I am not sure how to come to a numerical answer. Thanks in advance!
 

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rocapp said:
since I do not have a specified value for time or distance
You have an indirect one: At point 1, the position is 0. This allows to determine a value for the phase (kx-ωt+ϕ), which you can use in the equation for the velocity.