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Instantaneous Particle Velocity from Wave

  1. Jan 25, 2013 #1
    1. The problem statement, all variables and given/known data
    See the attached picture.



    2. Relevant equations
    D(x,t) = Asin(kx-ωt+ϕ)


    3. The attempt at a solution
    The instantaneous velocity of a particle would be the derivative of displacement:
    D'(x,t) = -ωAcos(kx-tω+ϕ)

    Then plug in the known values:
    = -18.84cos((π/15)x-3πt)

    The above should be the answer, but since I do not have a specified value for time or distance, I am not sure how to come to a numerical answer. Thanks in advance!
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     

    Attached Files:

  2. jcsd
  3. Jan 25, 2013 #2

    mfb

    User Avatar
    2016 Award

    Staff: Mentor

    You have an indirect one: At point 1, the position is 0. This allows to determine a value for the phase (kx-ωt+ϕ), which you can use in the equation for the velocity.
     
  4. Jan 25, 2013 #3
    Thanks!
     
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