Instantaneous Particle Velocity from Wave

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rocapp
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Homework Statement


See the attached picture.



Homework Equations


D(x,t) = Asin(kx-ωt+ϕ)


The Attempt at a Solution


The instantaneous velocity of a particle would be the derivative of displacement:
D'(x,t) = -ωAcos(kx-tω+ϕ)

Then plug in the known values:
= -18.84cos((π/15)x-3πt)

The above should be the answer, but since I do not have a specified value for time or distance, I am not sure how to come to a numerical answer. Thanks in advance!
 
Attachments
  • Snapshot graph of a sinusoidal wave on a string, D (cm) against x, with a 45 m/s rightward velocity arrow, a 30 cm wavelength marked, amplitude 2 cm, and points 1, 2 and 3 labelled on the curve.
    Screen shot 2013-01-25 at 2.06.12 PM.png
    29.3 KB · Views: 859
rocapp said:
since I do not have a specified value for time or distance
You have an indirect one: At point 1, the position is 0. This allows to determine a value for the phase (kx-ωt+ϕ), which you can use in the equation for the velocity.