- #1

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v = 50cos(100*pi*t - (pi/3))

I just need some material to help me deduce things such as the following:

* the peak to peak value of v (with two "^" on top)

* the RMS value of v

* mean or average value Von

* the period T

etc

Thanks.

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- Thread starter eximius
- Start date

- #1

- 29

- 0

v = 50cos(100*pi*t - (pi/3))

I just need some material to help me deduce things such as the following:

* the peak to peak value of v (with two "^" on top)

* the RMS value of v

* mean or average value Von

* the period T

etc

Thanks.

- #2

- 13

- 0

Normally we recieve 220Volts in the residence. Here 220V is the RMS(Root Mean Square) value. Approximately 311Volts peak value and 622Volts peak to peak value.

Peak Value(in volts) = RMS value(in volts) x square root of 2.

Peak to Peak Value(in volts) = 2 X Peak Value(in volts)

Example:

Peak Value(in volts) = 220V x 1.414 = 311V

Peak to Peak Value(in volts) = 2 x 311 = 622V

Our Voltmeter reads RMS value. Therefore we are getting 220V on voltmeter.

And about period, we are getting normally 50Hz frequency in residence. This means total 50 cycles of alternate waves in one second.

Period of one wave will be = 1/50 = 0.02 Seconds

- #3

berkeman

Mentor

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- 9,538

v = 50cos(100*pi*t - (pi/3))

I just need some material to help me deduce things such as the following:

* the peak to peak value of v (with two "^" on top)

* the RMS value of v

* mean or average value Von

* the period T

etc

Thanks.

This wikipedia page starts right off with the answers to your questions! Pretty neat.

http://en.wikipedia.org/wiki/Sinusoid

Now can you tell us the answers to those questions?

- #4

- 29

- 0

Vpeak = 50 V ,because the 50 is equal to A, which is the amplitude

Vp2p = 100 V ,because amplitude x 2

Vrms = 35.36 V ,because Vpeak = RMS x 2^0.5

Von = unsure about this one, don't know what it is really, the average of the AC voltage would be zero but I don't see how this would help

T =

ω = 2*pi*f

ω = 100*pi

.:. 100*pi = 2*pi*f

f = 50 Hz

T = 1/f

T = 1/50

T = 0.02s

Sorry for turning this into a sort of question thread, seems to be in the wrong forum now. If a mod feels that this is the case, could they please move it to the correct forum.

- #5

berkeman

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Vpeak = 50 V ,because the 50 is equal to A, which is the amplitude

Vp2p = 100 V ,because amplitude x 2

Vrms = 35.36 V ,because Vpeak = RMS x 2^0.5

Von = unsure about this one, don't know what it is really, the average of the AC voltage would be zero but I don't see how this would help

T =

ω = 2*pi*f

ω = 100*pi

.:. 100*pi = 2*pi*f

f = 50 Hz

T = 1/f

T = 1/50

T = 0.02s

Sorry for turning this into a sort of question thread, seems to be in the wrong forum now. If a mod feels that this is the case, could they please move it to the correct forum.

Looks good to me. And yes, the average value of that sinusoid is zero. It would be possible to add a DC term to it, in which case the average would not be zero:

v(t) = Vo + Acos(wt)

I'll go ahead and move this thread to the HH/Engineering forum. Good job!

- #6

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Edit: Oops. Just checked the digital version rather than the photocopied version I have. It's Vav not Von. Makes much more sense now.

Can't thank you guys enough. The help was very much appreciated.

- #7

berkeman

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Thanks again. But what exactly is Von? Not exactly an easy term to google seeing as I only get german results... :P

I don't know, actually. I've never seen that term used for an average value. Is it really shown as Von, or some other way? Is "on" two letters in the subscript? I'd guess the "n" is for nominal, and maybe Vo is the output voltage or something?

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