Insulator and conductor with electrostatic problems

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SUMMARY

The distinction between conductors and insulators in electrostatic problems is clear: the electric field within a conductor is always zero when in electrostatic equilibrium, while in insulators, the electric field can be non-zero. This principle is foundational to Gauss's law and Coulomb's law. Conductors allow current to flow in the presence of an electric field, whereas insulators do not, although all materials exhibit some level of conductivity. The classification of materials as conductors or insulators is somewhat arbitrary and depends on the specific voltage and current conditions.

PREREQUISITES
  • Understanding of Gauss's law
  • Familiarity with Coulomb's law
  • Basic knowledge of electric fields
  • Concept of electrostatic equilibrium
NEXT STEPS
  • Research the applications of Gauss's law in electrostatics
  • Explore the properties of materials in relation to conductivity
  • Study the concept of electrostatic shielding in conductors
  • Investigate the effects of voltage and current on material conductivity
USEFUL FOR

Physics students, electrical engineers, and anyone interested in understanding the principles of electrostatics and material properties related to conductivity.

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I was wondering, what is the distinction made with problems involving either conductors or insulators with electrostatic problems.

Is it that the electric field in an insulator doesn't have to be zero, whereas the electric field in a conductor is always 0?
 
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That's what experiments have shown and which were the basis for Gauss's law or the equivalent Coulomb's law.
 
A conductor is an object in which a current will flow for as long as an electric field is present inside the object. From which of course follows that if no current is flowing inside a conductor there can't be an electric field there.
However in practice every substance is at least slightly conductive. So where you draw the line between conductor and insulator is arbitrary and depends on what kind of voltage and current you are working with.
 

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