Integral Convergence/Divergence: 0 to ∞, 1/(1+x^6)^(1/2)

In summary, integral convergence and divergence refer to the behavior of an integral as the limits of integration approach infinity. The general method for determining the convergence or divergence of an integral is to evaluate the integral and see if it is finite or infinite. The formula for determining the convergence or divergence of an improper integral is to take the limit of the integral as the upper limit approaches infinity. To determine the convergence or divergence of a specific integral, techniques such as the comparison test can be used. The practical application of knowing the convergence or divergence of integrals is essential in making accurate predictions and solving problems in various fields of study.
  • #1
Lchan1
39
0

Homework Statement


Determine if the integral converges or diverges?
it;s the integral of 0 to infinity
of 1/(1+x^6)^(1/2)

Homework Equations



so I compared it with 1/x^2

The Attempt at a Solution



the answer key says it converges but i think it diverges since the integral of 1/x^2 diverges from 0 to 1...
 
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  • #2
1/x^2 is WAY GREATER than 1/(1+x^6)^(1/2) near 0. In fact, the latter function is bounded on [0,1]. The fact 1/x^2 diverges near zero doesn't prove your function does.
 

Related to Integral Convergence/Divergence: 0 to ∞, 1/(1+x^6)^(1/2)

What is the definition of integral convergence and divergence?

Integral convergence and divergence refer to the behavior of an integral as the limits of integration approach infinity. If the integral approaches a finite value as the limits approach infinity, it is said to converge. If the integral approaches infinity or does not have a finite value, it is said to diverge.

What is the general method for determining the convergence or divergence of an integral?

The general method for determining the convergence or divergence of an integral is to evaluate the integral using techniques such as substitution, integration by parts, or partial fractions. If the resulting integral is finite, the original integral is said to converge. If the resulting integral is infinite or does not exist, the original integral is said to diverge.

What is the formula for determining the convergence or divergence of an improper integral?

The formula for determining the convergence or divergence of an improper integral is to evaluate the integral from a lower limit to a finite number, and then take the limit of the resulting integral as the upper limit approaches infinity. If this limit is finite, the integral converges. If the limit is infinite or does not exist, the integral diverges.

How do you determine the convergence or divergence of the integral 0 to ∞, 1/(1+x^6)^(1/2)?

To determine the convergence or divergence of the integral 0 to ∞, 1/(1+x^6)^(1/2), we can use the comparison test. We compare this integral to the integral 0 to ∞, 1/x^3. Since the power of x in the denominator of the second integral is greater than the power of x in the denominator of the original integral, we can conclude that the original integral converges, as the second integral is known to converge.

What is the practical application of knowing the convergence or divergence of an integral?

The knowledge of integral convergence and divergence is important in various areas of science, such as physics and engineering. It allows for the prediction of the behavior of infinite series and can be used to solve problems involving infinite quantities. It is also used in statistics and probability to determine the probability of a certain event occurring. In short, understanding the convergence or divergence of integrals is essential in making accurate predictions and solving problems in various fields of study.

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