Integral Convergence/Divergence: 0 to ∞, 1/(1+x^6)^(1/2)

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SUMMARY

The integral of the function 1/(1+x^6)^(1/2) from 0 to infinity converges. This conclusion is based on a comparison with the function 1/x^2, which diverges from 0 to 1. However, the function 1/(1+x^6)^(1/2) is bounded on the interval [0,1], indicating that it does not diverge despite the behavior of 1/x^2. Therefore, the integral converges as confirmed by the answer key.

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  • Familiarity with convergence and divergence of integrals.
  • Knowledge of comparison tests for integrals.
  • Basic understanding of function behavior near critical points.
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Lchan1
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Homework Statement


Determine if the integral converges or diverges?
it;s the integral of 0 to infinity
of 1/(1+x^6)^(1/2)

Homework Equations



so I compared it with 1/x^2

The Attempt at a Solution



the answer key says it converges but i think it diverges since the integral of 1/x^2 diverges from 0 to 1...
 
Physics news on Phys.org
1/x^2 is WAY GREATER than 1/(1+x^6)^(1/2) near 0. In fact, the latter function is bounded on [0,1]. The fact 1/x^2 diverges near zero doesn't prove your function does.
 

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