Integral(F(x) Homework: Solving for Constants L, p, q, r

  • Thread starter Thread starter Hypercase
  • Start date Start date
  • Tags Tags
    Homework
Click For Summary
SUMMARY

The discussion centers on solving for constants L, p, q, and r in the function F(x) = p + qx + rx², given the conditions F(L) = 0 and F(0) = (1.5/L) * Integral(F(x), from 0 to L). The user has derived the equations p = -qL - rL² and p = -1.5qL - rL² but is uncertain about the next steps. A suggestion was made to evaluate F(0) by computing the integral, which the user has attempted without achieving further clarity on the problem.

PREREQUISITES
  • Understanding of polynomial functions and their properties
  • Knowledge of definite integrals and their applications
  • Familiarity with solving equations involving multiple variables
  • Basic calculus concepts, particularly integration techniques
NEXT STEPS
  • Compute the definite integral of F(x) from 0 to L
  • Explore the implications of the derived equations for p, q, and r
  • Investigate methods for solving systems of equations with multiple variables
  • Review techniques for verifying polynomial identities
USEFUL FOR

Students and educators in calculus, particularly those focusing on integral calculus and polynomial functions, as well as anyone involved in mathematical problem-solving involving constants and equations.

Hypercase
Messages
63
Reaction score
0
L,p,q,r are constants

F(x) = p + qx + rx^2
F(L) = 0
F(0) = (1.5/L) * Integral(F(x), from 0 to L)

show, F(x) = F(0) *(1-(x/L)^2)

I, have made several attempts, and I am not sure what to do.
I have determined
p = -qL - rL^2
and
p = -1.5qL - rL^2


how do i proceed?
-cheers
 
Physics news on Phys.org
Well firstly I would evaluate F(0) [i.e. compute the integral]. Then see if you can show that the statement holds.
 
evaluate F(0) [i.e. compute the integral]

I have done that, and ended up with

p = -1.5qL - rL^2,
that hasnt help and i don't know how to proceed.
 

Similar threads

Replies
4
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
2K
Replies
7
Views
2K
Replies
7
Views
2K
  • · Replies 22 ·
Replies
22
Views
5K