Integral of a special trigonometic functions

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SUMMARY

The integral discussed is $$\int_0^{2\pi}\frac{1+\cos[\alpha x]}{1+\sin x}dx$$ where ##\alpha## is an odd integer. The user reports that while specific values for ##\alpha## yield results in Mathematica, the general case with symbolic ##\alpha## does not return a computable result. Attempts to simplify the integrand using the relation $$\cos[\alpha x] = 2\cos x \cos[(\alpha-1)x] - \cos[(\alpha-2)x]$$ were unsuccessful. Additionally, it was noted that the integral does not converge.

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KFC
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Hi all,
I am working on the following integral

##
\int_0^{2\pi}\frac{1+\cos[\alpha x]}{1+\sin x}dx
##

where ##\alpha## is odd integer. Unless I set the ##\alpha## to a number then I can find the integral with mathematica easily. For general case with symbolic ##\alpha##, I cannot find the integral like this kind from any table and mathematica won't give the result as well. I am trying to apply the following relation to simplify the integrand

##
\cos[\alpha x] = 2\cos x \cos[(\alpha-1)x] - \cos[(\alpha-2)x]
##

it doesn't help to compute the integral. Any idea is welcomed. Thanks.
 
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Your integral does not converge.
 

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