ddddd28
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Is it possible to do an integral of f(x)*x without knowing f(x)?
The integral of f(x)*x cannot be determined without knowledge of f(x). Integration by parts is applicable, leading to the expression ∫xf(x)dx = x∫f(x)dx - ∫f(x)dx, but this requires knowing f(x). Additionally, using a dummy variable is recommended for clarity in integrals, as it avoids confusion with the variable of integration. The discussion emphasizes the importance of proper terminology, such as "limit of integration," in mathematical expressions.
PREREQUISITESMathematicians, calculus students, educators, and anyone interested in deepening their understanding of integration techniques and terminology.
ddddd28 said:Is it possible to do an integral of f(x)*x without knowing f(x)?
I am afraid that you've made a mistake.zinq said:Using integration by parts and letting u = x and dv = f(x)dx, we get
∫xf(x)dx = ∫udv = uv - ∫vdu = x∫f(x)dx - ∫f(x)dx
which is probably the most that can be said about the matter.
zinq said:Thank you for the correction! I should have written:
∫xf(w)dw = ∫xudv = uv]x - ∫xvdu = x∫xf(w)dw - ∫x(∫zf(w)dw)dz,
or maybe I should have just left it at
∫f(w)dw = uv - ∫vdu
and kept things simple.
zinq said:"What was wrong with x as the variable in the first place?"
To be technically correct, it's best to express an integral that ends up as being a function of (say) x in terms of integrating some variable that is not x (it doesn't matter which one). That's called a "dummy variable".
If the integral is indefinite and ends up to be a function of (say) x, then it needs an x, of course, and the proper place for the x is as a constant of integration. (Even though after the integral is taken, x need not be thought of as a constant.)
I hope that was sufficiently confusing (:-)>.
ddddd28 said:Is it possible to do an integral of f(x)*x without knowing f(x)?
zinq said:"Apart from a bit in the middle, that post is nonsense."
You are correct; I wrote "constant of integration" where I meant to say "limit of integration". I hope #7 no longer seems quite so nonsensical with that correction.