The integral of the square root of sine, represented as ∫√sin(x) dx, cannot be directly solved using the formula ∫u^(1/2) du = (2/3)u^(3/2) + C without proper substitution. The correct approach requires recognizing that if u = sin(x), then du = cos(x)dx must be included in the integral. Therefore, the initial claim that the integral equals -2/3cos(x)^(3/2) is incorrect due to the absence of the necessary differential component.
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\int \sqrt{sin(x)} dx = \int sin^{1/2}(x) dxcalculushelp said:Homework Statement
Find the Integral of \sqrt{sin(x)}
Homework Equations
none
The Attempt at a Solution
People say it's -2/3cos(x)^{3/2}
which I don't think so or is it?
thank you