Integral using Lebesgue Measure

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SUMMARY

The integral of the function f(x) defined as 3 for rational x and 2 for irrational x over the interval [0,1] can be computed using Lebesgue measure. The interval is partitioned into two disjoint sets: A (the rationals) and B (the irrationals). The measure of set A is zero since it is countable, while the measure of set B is equal to the length of the interval [0,1], which is 1. Therefore, the integral evaluates to 0 + 2 * 1 = 2.

PREREQUISITES
  • Understanding of Lebesgue measure and its properties
  • Familiarity with rational and irrational numbers
  • Knowledge of integration concepts, specifically Lebesgue integration
  • Basic set theory, including countable and uncountable sets
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  • Study Lebesgue integration techniques in detail
  • Explore the properties of Lebesgue measure in various contexts
  • Learn about the differences between Riemann and Lebesgue integrals
  • Investigate applications of Lebesgue measure in real analysis
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Mathematics students, particularly those studying real analysis or measure theory, as well as educators looking to deepen their understanding of integration techniques.

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Homework Statement


Find the integral of the function f(x)=3 when x is rational and 2 when x is irrational on the interval [0,1].

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The Attempt at a Solution


So I partition [0,1] into two disjoint sets A and B. [tex]A=[0,1] \cap Q[/tex] and [tex]B=[0,1] \cap Q^{c}[/tex].
Now the integral should be equal to 3 length(A) + 2 length(B). Since A is a countable set then its measure is zero. But I do not understand how to calculate the measure of B since it is uncountable.
 
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But you know what the measure of [0,1] is...
 
Thanks for the hint. So 1=len([0,1])=len(A)+len(B)=len(B).
 

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