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Integral using parseval (supposed to be simple )

  1. Oct 13, 2009 #1
    integral using parseval (supposed to be simple :( )

    Hi everyone. I am stuck in one of the assignment problems, and I think it's supposed to be simple, but it's just that I don't see how it worked out.

    I have to take integral(1/a^2+w^2)dw, from -a to a.
    I know the answer but I have no single clue how it came out.
    It would be great if someone could explain with steps :(
    Thank you and have a great day.
     
  2. jcsd
  3. Oct 14, 2009 #2
    Re: integral using parseval (supposed to be simple :( )

    Do you mean this?
    [tex]\int \frac{1}{a^2+w^2}dw = \frac{1}{a}\tan^{-1}\frac{w}{a}+c[/tex]

    or this?

    [tex]\int \left(\frac{1}{a^2}+{w^2}\right)dw = \ldots [/tex]

    Why Parseval?
     
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