Using Parseval's Theorem to evaluate an integral -- Help please

Click For Summary
SUMMARY

This discussion focuses on applying Parseval's Theorem to evaluate the integral ∫ dk sin^4(k)/(k^2) over the interval from negative to positive infinity. The function f(x) is defined piecewise as -1 for -2 ≤ x < 0, 1 for 0 ≤ x < 2, and 0 otherwise. The correct Fourier transform approach involves using the exponential factor e^(ikπx/2) to account for the periodicity of the function. The expected result of the integral is π/2, which the user struggles to derive despite multiple attempts.

PREREQUISITES
  • Understanding of Parseval's Theorem and its application in Fourier analysis.
  • Familiarity with Fourier Transform techniques and properties.
  • Knowledge of piecewise functions and their integration.
  • Basic skills in complex exponentials and trigonometric identities.
NEXT STEPS
  • Study the derivation and application of Parseval's Theorem in Fourier analysis.
  • Learn how to compute Fourier Transforms for piecewise functions.
  • Explore the properties of the sine function in Fourier series expansions.
  • Investigate the relationship between periodic functions and their Fourier representations.
USEFUL FOR

Students in advanced calculus or mathematical analysis, particularly those studying Fourier analysis and integral evaluation techniques.

KeithKp
Messages
4
Reaction score
0

Homework Statement


By applying Parseval's (Plancherel's) theorem to the function
7a9819bffa30e110228e3910e13a9c1.png
are given by:

f(x) = -1 for -2 ≤ x < 0
1 for 0 ≥ x < 2
0 otherwise

determine the value of the following integral.

∫ dk sin^4(k)/(k^2) (Integral between ±infinity)

Homework Equations



Parseval's Theorem, i.e the integral of the modulus squared of a function is equal to the integral of the modulus squared of its Fourier transform.

Fourier Transform formula.

The Attempt at a Solution



I've tried multiple times to try and arrive at the correct answer of pi/2 but I just can't do it. Is the Fourier transform:

∫-dx e^(ikx) + ∫ dx e^(ikx)? (First integral is between -2 and 0, second between 0 and 2). Because I can't get the correct answer doing that.

And for the equation of the function, is it just sgn(x), with the integral between -2 and 2? How else do I write f(x) given those boundaries? If I use sgn(x) between -2 and 2, I get 4 for the left hand side. But I still can't derive that integral.

If someone would just start me off with the correct Fourier transform equation, i'll go away and crunch the integration myself.

Thank you.
 
Last edited by a moderator:
Physics news on Phys.org
KeithKp said:
(First integral is between -2 and 0, second between 0 and 2)
Yes, but then you need to adjust the exponential factor, since eikx is periodic with period 2π, not 4. Try eikπx/2.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K