Integrate 3cos^2(x): Step by Step Solution

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Homework Help Overview

The discussion revolves around the integration of the function 3cos²(x). The original poster seeks a step-by-step solution for this integration, mentioning a differential equation context with specific values for y and x.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of trigonometric identities to simplify the integration process, particularly the relationship between cos²(x) and cos(2x). Questions arise about the appropriate methods for integration, including integration by parts and the application of double angle formulas.

Discussion Status

Several participants have offered guidance on using trigonometric identities to facilitate integration. There is an ongoing exploration of different approaches, with some participants expressing confusion about the relationships between the functions involved. The discussion remains active, with no clear consensus reached yet.

Contextual Notes

Some participants express anxiety about upcoming exams, which may affect their understanding and engagement in the discussion. There is mention of needing to memorize or derive common trigonometric identities to aid in integration tasks.

  • #31


One last thing, Umm I want to ask another question that does not really need a new thread.

In integration by parts, which function has the priority to be substituted as U

I follow the method of LITE
L = Logs and Ln
I = Indices
T = Trig Functions
E = Exponents

But integrating e^x.Cos(x)

The answer booklet chose e^x as U ... :S :S why is that ?

Which one has a priority to be replaced in U when we have a Trig function and an exponent function
 
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  • #32


It really doesn't matter which one you take in this case and don't forget LITE is a rule of thumb and it is not always the best course of action.
 
  • #33


I tried taking the trig function for U
but the answer sheet gives a different answer, it used u = exponential function

What way do you recommend ?
 
  • #34


Personally, I wouldn't use integration by parts to evaluate the integral of excos(x). If you know Euler's formula you can transform the cosine into the real part of a complex exponential, the integration then becomes straightforward.
 
  • #35


Hmmm, I really do not know Euler's formula, my exam is tomorrow so I don't think I would be very safe learning it today, might mix up tomorrow.

So other than Euler's formula, is using LITE good enough ? Our tutor told us to use LITE, so perhaps in the exam ill just indicate that I am using THAT method, the one they taught us. In this case I should not lose marks (I hope) because its been told by them to use LITE method.

If you have a better method other than Euler's formula, please tell me what it is.

Thank you very much, really appreciated.
 
  • #36


ZaZu said:
Hmmm, I really do not know Euler's formula, my exam is tomorrow so I don't think I would be very safe learning it today, might mix up tomorrow.

So other than Euler's formula, is using LITE good enough ? Our tutor told us to use LITE, so perhaps in the exam ill just indicate that I am using THAT method, the one they taught us. In this case I should not lose marks (I hope) because its been told by them to use LITE method.

If you have a better method other than Euler's formula, please tell me what it is.

Thank you very much, really appreciated.
The LITE method is fine.
 
  • #37


Hmm so I should ignore what this answer sheet is telling me, because its following a different method other than LITE.
Its substituting e for U instead of cosx ..

Thanks :)
 
  • #38


I get the same answer regardless whether I use u=e^x or u=cos x. I reckon you made an error with some minus signs, it's the only error I can really think of in this problem.

Whether you ignore the sheet or not you should get the same answer that is : \frac{1}{2} e^x(\cos x+\sin x)
 
  • #39


Hmm I think I do have some errors in the signs.

The answer in the sheet is :

http://img149.imageshack.us/img149/7731/image357f.jpg

So you're right, using whatever way its the same answer !
 
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  • #40


I don't know what's this LITE thing, and never had to use it. I look at it this way:

There are 4 forms of products of functions:

(1) Only one function is integrable

a. function with another function that cannot be integrated (e.g. sin(ln x), tan^-1(x) ln, lg etc.)
--> differentiate the non-integrable function, integrate the other function
--> e.g. x^3 ln(x), x tan^-1 (x)

b. a constant with a function that cannot be integrated
--> differentiate the non-integrable function, integrate the constant
--> e.g. ln x = 1 * ln(x), sin(ln x) = 1 * sin(ln x)

(2) Both functions are integrable

a. only one turns into a constant after a few differentiations, the other does not
--> differentiate the one that turns into a constant, integrate the other
--> repeat integration by parts until reduced to constant
--> e.g. x * sin(x), x^2 * e^(2x)

b. neither turns into a constant after a few differentiations
--> differentiate either of the two, integrate the other
--> shift the newly generated integral once it takes the same form as the given integral to the left hand side of the equation, then divide both sides
--> e.g. e^x * sin x, e^(2x) * cos 2x

So the the one you've asked falls under the last category. You can choose to integrate either one of them. But I usually apply Euler's formula for the one you've asked (search google for "complexifying the integral") because the rule of the thumb is to use the easiest/fastest method - and integration by parts tends not to be. But don't bother learning the use of Euler's formula here now if you haven't done an introduction to complex numbers.

Instead, I think you might benefit if you tried integrating the 4x2 examples that I've given above so that you can get used to the various forms.
 
  • #41


I just checked back on this topic !

Thank you very much ephedyn, that was really helpful !
Thank you ! REally appreciated :) :)
 
  • #42


Mmhmm, no problem. Are you in high school? If you need any more help in math or physics you could send me a private message here, I'll try to help where I can.
 

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