Playwithmeee Messages 2 Reaction score 0 Thread starter Jun 12, 2006 #1 I have a math final tommorow help please! How do I integrate e^(x^1/3) Thank you !
arunbg Messages 594 Reaction score 0 Jun 12, 2006 #2 Please show your working . Just to get you started, Let x^1/3 = t . dx = 3x^(2/3)dt = 3t^2dt Can you go from here ?
Please show your working . Just to get you started, Let x^1/3 = t . dx = 3x^(2/3)dt = 3t^2dt Can you go from here ?
Playwithmeee Messages 2 Reaction score 0 Jun 12, 2006 #3 How did you go from dx = 3x^(2/3)dt to 3t^2dt Ok I think I get what to do next, substiture dx into the orignal equation? Last edited: Jun 12, 2006
How did you go from dx = 3x^(2/3)dt to 3t^2dt Ok I think I get what to do next, substiture dx into the orignal equation?
benorin Science Advisor Insights Author Messages 1,442 Reaction score 191 Jun 12, 2006 #4 [tex]dx = 3x^{\frac{2}{3}} dt=3\left( x^{\frac{1}{3}}\right) ^{2} = 3t^2dt[/tex]