Integrate (x^3 + x^2)/(1 + x^4) using substitution?

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SUMMARY

The integration of the function (x^3 + x^2)/(1 + x^4) can be approached using substitution and partial fraction decomposition. Users in the discussion suggested substituting u = x^4 + 1, leading to the integral 0.25∫(1/(u√(u-1))) du. Additionally, factoring 1 + x^4 into two quadratics is recommended for partial fraction decomposition, specifically into (1 - √2x + x^2)(1 + √2x + x^2). The discussion highlights the challenges faced in solving for constants A and B in the partial fractions.

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ritwik06
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Integrate the following:

(x^3+x^2)/(1+x^4)

I have been taught only integration by substitution. My teacher told me that this can be solved using that ith some trick.

I have tried for a long time. All that I can do was to convert the numerator to x^2(x+1)
and the denominator to (x^2-1)^2+2x^2
but without sucess.

Next I tried to break the given thing into two terms. it helped a little but I was again stuck on the second term, ie. , i couldn't again find out the integration of x^2/(1+x^4)



Please hlp me. Its maddening.
 
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Is it easy to find the integral of (x^2)/(1+x^4)
Please help me?
 
I have not tried this, but you could try factoring 1+x^4 into two quadratics, then do partial fraction decomposition.
 
\int\frac{x^{2}}{1+x^{4}}

Can this be determined?
 
Big-T said:
I have not tried this, but you could try factoring 1+x^4 into two quadratics, then do partial fraction decomposition.

its difficult to factorize x^{4}+1.
Moreover,
can u please tell me about partial fractions decomposition? I haven't learned it yet.
 
ritwik06 said:
\int\frac{x^{2}}{1+x^{4}}

Can this be determined?

Have you tried the obvious substitution u= x4+ 1??
 
HallsofIvy said:
Have you tried the obvious substitution u= x4+ 1??
yes,
it yields the following:
0.25\int\frac{1}{u \sqrt[4]{(u-1)}}du
But does this help or more complicate the problem?
 
Last edited:
Please help? If u think it can't be done with substitution. Please tell me about the other method, if any. Just a brief idea.
 
1+x^4 = 1+2x^2+x^4 - 2x^2=(1+x^2)^2-2x^2=(1-\sqrt 2 x + x^2)(1+\sqrt 2 x+x^2).

As to partial fraction decomposition, I suggest you have a look in your textbook or at wikipedia or other webpages.
 
  • #10
Big-T said:
1+x^4 = 1+2x^2+x^4 - 2x^2=(1+x^2)^2-2x^2=(1-\sqrt 2 x + x^2)(1+\sqrt 2 x+x^2).

As to partial fraction decomposition, I suggest you have a look in your textbook or at wikipedia or other webpages.

Yeah, I have read now about partial fractions. It means to cahnge the given thing into sum of 2 fractions. But hile trying to change:
\frac{x^{2}}{1+x^{4}}
in the form of
\frac{A}{1-x\sqrt{2}+x^{2}}+\frac{B}{1+x\sqrt{2}+x^{2}}
I get the following equation:
x^{2}=(A+B)x^{2}+(A+B)(2\sqrt{x}+1)

I cannot solve further for A and B. Can u do it?

Its one hell out of the other. What should I do? Please help me! and try it out before answering. Thanks for all efforts!
 
  • #11
Anyone going to help me out? Please!
 
  • #12
Your fractions should be of the form:
\frac{Ax+B}{1-x\sqrt{2}+x^{2}} + \frac{Cx+D}{1+x\sqrt{2}+x^{2}}.
 

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