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If you look at the answer you will see that they integrate sin^{4}3x into (sin^{5}3x)/5. well, if you can do that why not just integrate 3cos^{5}3xdx into (cos^{6}3xdx)/2? why go through all the trouble of dividing it into parts? it is true that (cos^{6}3xdx)/2 = 0 but i still don't see why you can integrate sin^{4}3x and not 3cos^{5}3xdx.

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# Homework Help: Integrating 3cos[SUP]5[/SUP]3xdx

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