Finding volume using integration

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SUMMARY

The discussion centers on calculating volume using the definite integral formula ∫A(x)dx, where A(x) represents the cross-sectional area. The user attempted to find the volume by integrating the function ∫4x²dx from 0 to 5, arriving at an incorrect result of 500/3. The error identified was that the user integrated the height instead of the area, indicating a misunderstanding of the application of the formula.

PREREQUISITES
  • Understanding of definite integrals in calculus
  • Familiarity with cross-sectional area concepts
  • Knowledge of polynomial functions and their integration
  • Basic skills in evaluating integrals
NEXT STEPS
  • Review the concept of cross-sectional area in volume calculations
  • Practice integrating polynomial functions, specifically ∫4x²dx
  • Study the application of definite integrals in real-world volume problems
  • Learn about common mistakes in integral calculus and how to avoid them
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Students studying calculus, educators teaching integration techniques, and anyone interested in understanding volume calculations through definite integrals.

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Homework Statement
The base of the solid is a square, one of whose sides is the interval [0,5] along the the x-axis.
The cross sections perpendicular to the x-axis are rectangles of height f(x)=4x^2. Compute the volume of the solid.
Relevant Equations
f(x)=4x^2
I know that the formula for volume is equal to the definite integral ∫A(x)dx, where A(x) is the cross sectional. I found the definite integral where b=5 and a=0, for ∫4x2dx. I obtained the answer 500/3, however this was incorrect, and I'm unsure of where I went wrong?

Thank you.
 
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You have not integrated the area, you have integrated the height.
 

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