Integrating a Monster: Achieving a Solution with Elegance

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SUMMARY

The discussion focuses on integrating the function \(\int_{0}^{\pi/2} \cos(\theta) \frac{\exp\left ( \frac{-2\pi(1-\cos(\theta))^2}{k^2}\right ) }{erf\left(\frac{2\pi}{k}\right)} d\theta\). Participants suggest that since the error function \(erf\) is independent of \(\theta\), it can be factored out of the integral. The primary methods proposed for tackling this integration include power series expansion and contour integration, although both approaches present their own complexities.

PREREQUISITES
  • Understanding of integral calculus, specifically definite integrals.
  • Familiarity with the error function \(erf\) and its properties.
  • Knowledge of power series expansions and their applications in integration.
  • Basic concepts of contour integration in complex analysis.
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  • Research techniques for power series expansion in integration.
  • Study the properties and applications of the error function \(erf\).
  • Explore contour integration methods in complex analysis.
  • Investigate numerical integration techniques for complex functions.
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Mathematicians, physicists, and students engaged in advanced calculus or complex analysis, particularly those dealing with integrals involving special functions like the error function.

H_man
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[tex]\int_{0}^{\pi/2}(cos(\theta)*exp(-2[\pi(1-cos(\theta))]^2)/k^2)/erf(2\pi/k)[/tex]

Where of course the error function erf is defined as:
[tex] erf(x)=2/\pi\int_{0}^{x}exp(-t^2)dt[/tex]

Anyway... this is the problem I want to integrate. I am not looking for someone to post a solution. My question is simply what is the best way of tackling this monster. My first thought is to expand each of the functions into a power series and use the "crank the handle" method. Not very elegant. Can anyone see a better/quicker method?

Thanks

Harry
 
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[tex] \int_{0}^{\pi \over 2} cos(\theta) \frac{\exp\left ( \frac{-2\pi(1-cos\theta)^2}{k^2}\right ) }{erf(\frac{2\pi}{k})}d\theta[/tex]

Now, since erf doesn't depend on theta, you can take it out of the integral. After that, your best bet is to try series. It's possible you might be able to do this with contour integrals, although that might be equally as difficult, if even possible.
 
Cheers!
 

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