Integrating a Tricky Differential Equation with a Square Root Fraction

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PhysicsLad
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Homework Statement


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Solve the differential equation

Differential equation: (1 + y^2) dx - (y - sqrt(1 + y)) (1 + x)^(3/2) dy = 0.

Homework Equations

The Attempt at a Solution


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Handwritten notes titled Differential equations on lined paper, showing separated integrals of (1+x)^(-3/2) dx and (y - sqrt(1+y))/(1+y^2) dy, with a crossed-out line 1+y=0 and a split of the y-term integral.
I just can't integrate that (1+y)^(1/2)/(1+y^2)dy at the end... the other two integrals are trivial.
 
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  • Differential equation: (1 + y^2)dx - (y - sqrt(1 + y)) (1 + x)^(8/3) dy = 0.
    DiffEq001.png
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  • Handwritten notes titled Differential equations on lined paper, showing separated integrals of (1+x)^(-3/2) dx and (y - sqrt(1+y))/(1+y^2) dy, with a crossed-out step and a split integral below.
    IMG_20160624_224152.jpg
    31.4 KB · Views: 679
Try the substitution ##u=\sqrt{1+y}## and see where that gets you.
 
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I actually tried before posting. Once you make the substitution there are two ways to attempt the problem, one by doing u^2 = 1+y and then differentiating, and the other got me to 2*(1+y)^(1/2)du = dy. None of these seemed to make the integral any easier.